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A black body, at a temperature of $227\,^oC$ radiates heat at a rate of $7\,cal\,cm^{-2}\, s^{-1}$ . At a temperature of $727\,^oC$ , the rate of heat radiated in the same units will be
Solar radiation emitted by sun resembles that emitted by a black body at a temperature of $6000 K$ . Maximum intensity is emitted at a wavelength of about $4800Å$ . If the sun were to cool down from $6000 K$ to $3000 K$ then the peak intensity would occur at a wavelength ....... $\overset{o}{\mathop{A}}\,$
Spheres $P$ and $Q$ are uniformly constructed from the same material which is a good conductor of heat and the radius of $Q$ is thrice the radius of $P$. The rate of fall of temperature of $P$ is $x$ times that of $Q$ when both are at the same surface temperature. The value of $x$ is :
A body of length 1m having cross sectional area $0.75\;m^2$ has heat flow through it at the rate of $ 6000\; Joule/sec$ . Then find the temperature difference if $K = 200\;J{m^{ - 1}}{K^{ - 1}}$ ...... $^oC$