A block of mass $5\, kg$ is $(i)$ pushed in case $(A)$ and $(ii)$ pulled in case $(B)$, by a force $F = 20\, N$, making an angle of $30^o$ with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is $\mu = 0.2$. The difference between the accelerations of the block, in case $(B)$ and case $(A)$ will be $....... ms^{-2}$ .$(g = 10\, ms^{-2})$
JEE MAIN 2019, Medium
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${N_1} = 60 {N_2} = 40$
${a_1} = \frac{{10\sqrt 3 - 02 \times 60}}{5} {a_2} = \frac{{10\sqrt 3 - 0.2 \times 40}}{5}$
${a_1} - {a_2} = 0.8$
${a_1} = \frac{{10\sqrt 3 - 02 \times 60}}{5} {a_2} = \frac{{10\sqrt 3 - 0.2 \times 40}}{5}$
${a_1} - {a_2} = 0.8$
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