Assuming the coefficient of friction between the road and tyres of a car to be $0.5$, the maximum speed with which the car can move round a curve of $40.0\, m$ radius without slipping, if the road is unbanked, should be ......... $m/s$
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(c)$v = \sqrt {\mu gr} = \sqrt {0.5 \times 9.8 \times 40} = \sqrt {196} = 14\;m/s$
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