MCQ
A block of mass $m$ is kept on a platform which starts from rest with constant acceleration $g/2$ upward, as shown in figure. Work done by normal reaction on block in time $t$ is
  • A
    $ - \frac{{m{g^2}{t^2}}}{8}$
  • B
    $  \frac{{m{g^2}{t^2}}}{8}$
  • C
    $0$
  • $  \frac{{3m{g^2}{t^2}}}{8}$

Answer

Correct option: D.
$  \frac{{3m{g^2}{t^2}}}{8}$
d
$\begin{array}{l}
W = F\cos \theta \\
\,\,\,\,\,\, = m\left( {g + \frac{g}{2}} \right) \times \left[ {\frac{1}{2} \times \frac{g}{2} \times {t^2}} \right]
\end{array}$

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