A bob of mass $'m'$ suspended by a thread of length $l$ undergoes simple harmonic oscillations with time period ${T}$. If the bob is immersed in a liquid that has density $\frac{1}{4}$ times that of the bob and the length of the thread is increased by $1 / 3^{\text {rd }}$ of the original length, then the time period of the simple harmonic oscillations will be :-
  • A${T}$
  • B$\frac{3}{2} {T}$
  • C$\frac{3}{4} {T}$
  • D$\frac{4}{3} {T}$
JEE MAIN 2021, Diffcult
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