A body cools in $7$ minutes from $60^{\circ}\,C$ to $40^{\circ}\,C$. The temperature of the surrounding is $10^{\circ}\,C$. The temperature of the body after the next $7$ minutes will be
JEE MAIN 2023, Medium
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using average rate of Newton's law of cooling
$\frac{T_1-T_2}{t}=K\left(\frac{T_1+T_2}{2}-T_s\right)$
Given $\frac{60-40}{7}=K(50-10) \ldots$ (i)
$\frac{40-T}{7}=K\left(\frac{40+T}{2}-10\right) \ldots$ (ii)
From $(i)$ and $(ii)$
$T =28^{\circ}\,C$
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