MCQ
A body is moving along a rough horizontal surface with an initial velocity $6\,\,m/s.$ If the body comes to rest after travelling $9\, m$, then the coefficient of sliding friction will be
- A$0.4$
- ✓$0.2$
- C$0.6$
- D$0.8$
$\therefore \mu = \frac{{{u^2}}}{{2gs}} = \frac{{{{(6)}^2}}}{{2 \times 10 \times 9}} = 0.2$
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$\text{y}=3\cos\Big(\frac{\pi}{4}-2\omega\text{t}\Big)$
The motion of the particle is:
