Question
A body of mass 10 g is 6cm performs simple harmonic motion on a long line, its maximum speed is $12 ~\text {cm / second}$. Find the period and maximum potential energy.

Answer

Given :
$\begin{aligned}A & =3 cm, \omega=\frac{v_{\max }}{A}=\frac{12}{3} \\\omega & =4 \text { radian } / sec . \\T & =\frac{2 \pi}{\omega}=\frac{2 \pi}{4}=\frac{2 \times 3.14}{4} \\T & =1.57 \text { second }\end{aligned}$
Maximum potential energy
$\begin{array}{l}U=\frac{1}{2} m^2 A^2 \\U=\frac{1}{2} \times 10 \times 10^{-3} \times 4 \times 4 \times 3 \times 3 \times 10^{-4} \\U=720 \times 10^{-7} \text { joules }\end{array}$

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