PART - 1 CH - 4 Laws of Motion — Physics STD 11 Science — Question
Gujarat BoardEnglish MediumSTD 11 SciencePhysicsPART - 1 CH - 4 Laws of Motion2 Marks
Question
The velocity of the jet of rocket is $9 km / s$. If 300 kg gas is deposited every second, find the force applied on the rocket
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Answer
It is given, $\begin{aligned} v & =9 km / s \\ v & =9000 m / s \\ \frac{d m}{d t} & =300 kg / sec \end{aligned}$ Force applied on rocket : $\begin{aligned} F & =v \times \frac{d m}{d t} \\ & =9000 \times 300\\ \Rightarrow \quad & =27 \times 10^5 N \\ \Rightarrow \quad F & =2.7 \times 10^6 N\quad \text { Ans. } \end{aligned}$
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