A body of mass $10\,kg$ is moving with an initial speed of $20\,m / s$. The body stops after $5\,s$ due to friction between body and the floor. The value of the coefficient of friction is (Take acceleration due to gravity $g =10\; ms ^{-2}$)
JEE MAIN 2023, Medium
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$a=-\mu g$
$\because v=u+a t$
$0=20+(-\mu \times 10) \times 5$
$50 \mu=20$
$\mu=\frac{2}{5}=0.4$
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