A body of mass $1\,kg$ is executing simple harmonic motion. Its displacement $y(cm)$ at $t$ seconds is given by $y = 6\sin (100t + \pi /4)$. Its maximum kinetic energy is ..... $J$
A$6$
B$18$
C$24$
D$36$
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B$18$
b (b) So $a = 6cm,\;\omega = 100\,rad/\sec $
${K_{\max }} = \frac{1}{2}m{\omega ^2}{a^2}$
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