A body performs $S.H.M.$ Its kinetic energy $K$ varies with time $t$ as indicated by graph
Medium
Download our app for free and get startedPlay store
(a) Kinetic energy varies with time but is never negative.
 
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A particle is performing simple harmonic motion along $x-$axis with amplitude $4 \,cm$ and time period $1.2\, sec$. The minimum time taken by the particle to move from $x =2 ,cm$ to $ x = + 4\, cm$ and back again is given by .... $\sec$
    View Solution
  • 2
    The velocity of a particle in simple harmonic motion at displacement $y$ from mean position is
    View Solution
  • 3
    The total energy of a particle executing S.H.M. is proportional to
    View Solution
  • 4
    A simple pendulum oscillates in air with time period $T$ and amplitude $A$. As the time passes
    View Solution
  • 5
    Acceleration of a particle, executing $SHM$, at it’s mean position is
    View Solution
  • 6
    A body oscillates with a simple harmonic motion having amplitude $0.05\, m .$ At a certain instant, its displacement is $0.01\, m$ and acceleration is $1.0 \,m / s ^{2} .$ The period of oscillation is
    View Solution
  • 7
    Three masses $700g, 500g$, and $400g$ are suspended at the end of a spring a shown and are in equilibrium. When the $700g$ mass is removed, the system oscillates with a period of $3$ seconds, when the $500 \,gm$ mass is also removed, it will oscillate with a period of ...... $s$
    View Solution
  • 8
    The time period of oscillations of a simple pendulum is $1$ minute. If its length is increased by $44 \%$. then its new time period of oscillation will be ......... $s$
    View Solution
  • 9
    The kinetic energy of $SHM$ is $1/n$ time its potential energy. If the amplitude of the $SHM$ be $A$, then what is the displacement of the particle?
    View Solution
  • 10
    Two particles are in $SHM$ on same straight line with amplitude $A$ and $2A$ and with same angular frequency $\omega .$ It is observed that when first particle is at a distance $A/\sqrt{2}$ from origin and going toward mean position, other particle is at extreme position on other side of mean position. Find phase difference between the two particles
    View Solution