MCQ
A body starts with an initial velocity of $10\,ms ^{-1}$ and is moving along a straight line with constant acceleration. When the velocity of the particle is $50\,ms ^{-1}$, the acceleration is reversed in direction. The velocity of the particle when it again reaches the starting point is $............\,m/s^{-1}$
  • $70$
  • B
    $60$
  • C
    $10$
  • D
    $30$

Answer

Correct option: A.
$70$
a
(a)

$(50)^2=(10)^2+2 a s$

Now, $\quad v^2=(50)^2+2(-a)(-s)=(50)^2+2 a s$

Solving these two equations, we get

$v=70\,m / s$

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