MCQ
A bomb of mass $12\,\,kg$ at rest explodes into two fragments of masses in the ratio $1 : 3.$ The $K.E.$ of the smaller fragment is $216\,\,J.$ The momentulm of heavier fragment is (in $kg-m/sec$ )
- ✓$36$
- B$72$
- C$108$
- DInsufficient data
✓
Answer
Correct option: A.
$36$
a
$\mathrm{M}_{1} \mathrm{E}_{1}=\mathrm{M}_{2} \mathrm{E}_{2} \quad \Rightarrow \mathrm{E}_{2}=72 \mathrm{J}$
$\mathrm{M}_{1} \mathrm{E}_{1}=\mathrm{M}_{2} \mathrm{E}_{2} \quad \Rightarrow \mathrm{E}_{2}=72 \mathrm{J}$
$\Rightarrow \mathrm{P}_{2}=\sqrt{2 \times 9 \times 72}$
$\mathrm{P}_{2}=36 \mathrm{kg} \mathrm{m} / \mathrm{s}$
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