Question
A box contains $5$ strawberry chocolates, $6$ coffee chocolates and $2$ peppermint
chocolates. If one of the chocolates is picked from the box at randomly, Find the
probability of the following events by completing the activity.
(i) Event A : it is a coffee chocolate. 
(ii) Event B : it is a peppermint chocolate.Activity : Let 'S' is the sample space.

$\therefore n(S) = 5+6+2 = 13$

(i) Event A : it is a coffee chocolate
$\therefore n(A) =$ ………… 
$\therefore P(A) = \frac{\square}{n(S)}$ ………… Formula
$\therefore P(A)=\frac{\square}{13}$

(ii) Event B : it is a peppermint chocolate.
$\therefore n(B) =$ ………… 
$\therefore P(B) =\frac{\square}{n(S)}$ ………… Formula
$\therefore P(B) =\frac{\square}{13}$

Answer

Let 'S' be the sample space.
$\therefore \mathrm{n}(\mathrm{S})=5+6+2=13$
Event B : it is a peppermint chocolate.
$\therefore n(B)=2$
$\therefore P(B)=\frac{n(B)}{n(S)} \quad \ldots ..$ Formula
$\therefore P(B)=\frac{2}{13}$

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