MCQ
A box contains coupons labelled $1,2, \ldots, 100$. Five coupons are picked at random one after another without replacement. Let the numbers on the coupons be $x_1, x_2, \ldots, x_5$. What is the probability that $x_1 > x_2 > x_3$ and $x _3 < x _4 < x _5 ?$
  • A
    $1 / 120$
  • B
    $1 / 60$
  • $1 / 20$
  • D
    $1 / 10$

Answer

Correct option: C.
$1 / 20$
c
(c)

We have,$100$ coupons labelled $1$ , $2,3, \ldots 100$

Five coupons are random selected and arranged.

$\therefore$ Total numbers of outcomes $={ }^{110} C_5 \times 5$ !

Five coupons $x_1, x_2, x_3, x_4, x_5$ are arranged such that $x_1 > x_2 > x_3$ and

$x_3 < x_4 < x_5$

Favourable outcomes $={ }^{100} C_5 \times \frac{4 !}{2 ! 2 !}$

$\therefore \text { Required probability } =\frac{{ }^{100} C_5 \times \frac{4 !}{2 ! 2 !}}{{ }^{100} C_5 \times 5 !}$

$=\frac{1}{20}$

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