MCQ
If $2{\tan ^{ - 1}}(\cos x) = {\tan ^{ - 1}}(2{\rm{cosec }}x),$ then  $x =$
  • A
    $\frac{{3\pi }}{4}$
  • $\frac{\pi }{4}$
  • C
    $\frac{\pi }{3}$
  • D
    None of these

Answer

Correct option: B.
$\frac{\pi }{4}$
b
(b) We have $2$ ${\tan ^{ - 1}}(\cos x) = {\tan ^{ - 1}}(2\cos {\rm{ec}}x)$

==> ${\tan ^{ - 1}}\left( {\frac{{2\cos x}}{{1 - {{\cos }^2}x}}} \right)$$= {\tan ^{ - 1}}(2\,{\rm{cosec }}x)$

$\frac{{2\cos x}}{{{{\sin }^2}x}} = 2{\rm{cosec}}\,x \Rightarrow 2\cos x = 2\sin x$

or $\sin x = \cos x$

$ \Rightarrow x = \frac{\pi }{4}$.

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