A boy of mass $4\, kg$ is standing on a piece of wood having mass $5 \,kg$. If the coefficient of friction between the wood and the floor is $0.5,$ the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is ......$N.$(Round off to the Nearest Integer) [Take $g=10 \,ms ^{-2}$ ]
JEE MAIN 2021, Difficult
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$N + T =90$
$T =\mu N =0.5(90- T )$
$1.5 T =45$
$T =30$
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