A capacitor $C = 100$ $ \mu F$ is connected to three resistor each of resistance $1$ $k\Omega$ and a battery of $emf$ $9\,V$. The switch $S$ has been closed for long time so as to charge the capacitor. When switch $S$ is opened, the capacitor discharges with time constant......$ms$
Diffcult
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$\therefore$ Time constant
$\lambda=\mathrm{RC}=0.5 \times 10^{3} \times 100 \times 10^{-6}$
$=50 \times 10^{-3} \mathrm{S}=50 \mathrm{m} / \mathrm{s}$
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