$\mathrm{C}_1=\frac{2 \in_0 \mathrm{~A}}{2 \times \mathrm{d}}=10 \mu \mathrm{F}$

$\mathrm{C}_2=\frac{3 \in_0 \mathrm{~A}}{2 \mathrm{~d}}=15 \mu \mathrm{F}$

$\mathrm{C}_{\mathrm{eq}}=25 \mu \mathrm{F}$

Now the charge on

$\mathrm{C}_1=10 \mathrm{~V} \mu \mathrm{c}$

$\mathrm{C}_2=1.5 \mathrm{~V} \mu \mathrm{C}.$

Now force between the plates $\left[\mathrm{F}=\frac{\mathrm{Q}^2}{2 \mathrm{~A} \in_0}\right]$

$\frac{100 \mathrm{~V}^2 \times 10^{-12}}{2 \times 2 \times 10^{-4} \in_0}+\frac{225 \mathrm{~V}^2 \times 10^{-12}}{2 \times 2 \times 10^{-4} \times \in_0}=8$

$325 \mathrm{~V}^2=8 \times 4 \times 10^{-4} \times 8.85$

$\mathrm{~V}^2-\frac{32 \times 8.85 \times 10^{-4}}{325}$

$\therefore \mathrm{V}=\sqrt{\frac{283.2 \times 10^{-4}}{325}}$

$\mathrm{~V}=0.93 \times 10^{-2}$