MCQ
A capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity, the potential difference across the combination becomes $V$. The unknown capacitance is
- A$C\left( {\frac{{{V_0}}}{V}} \right)$
- B$C\left( {\frac{{{V_0}}}{V} + 1} \right)$
- ✓$C\left( {\frac{{{V_0}}}{V} - 1} \right)$
- D$CV$
