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A capacitor of capacity ${C_1}$ is charged upto $V$ volt and then connected to an uncharged capacitor of capacity ${C_2}$. Then final potential difference across each will be
  • A$\frac{{{C_2}V}}{{{C_1} + {C_2}}}$
  • B$\left( {1 + \frac{{{C_2}}}{{{C_1}}}} \right)\,V$
  • C$\frac{{{C_1}V}}{{{C_1} + {C_2}}}$
  • D$\left( {1 - \frac{{{C_2}}}{{{C_1}}}} \right)\,V$
AIPMT 2002, Medium
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