Question
A capacitor stores $50\mu\text{C}$ charge when connected across a battery. When the gap between the plates is filled with a dielectric, a charge of $100\mu\text{C}$ flows through the battery. Find the dielectric constant of the material inserted.

Answer


Initial charge stored $=50\mu\text{c}$

Let the dielectric constant of the material induced be ‘k’.

Now, when the extra charge flown through battery is 100.

So, net charge stored in capacitor $=150\mu\text{c}$

Now, $\text{C}_1=\frac{\in_0\text{A}}{\text{d}}$ or $\frac{\text{q}_1}{\text{V}}=\frac{\in_0\text{A}}{\text{d}}\ \dots(1)$

$\text{C}_2=\frac{\in_0\text{Ak}}{\text{d}}$ or $\frac{\text{q}_2}{\text{V}}=\frac{\in_0\text{Ak}}{\text{d}}\ \dots(2)$

Dividing (1) and (2) we get $\frac{\text{q}_1}{\text{q}_2}=\frac{1}{\text{k}}$

$\Rightarrow\frac{50}{150}=\frac{1}{\text{k}}$

$\Rightarrow\text{k}=3$

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