A capacitor with capacitance $5\,\mu F$ is charged to $5\,\mu C.$ If the plates are pulled apart to reduce the capacitance to $2\,\mu F,$ how much work is done?
  • A$3.75\times 10^{-6}\,J$
  • B$2.55\times 10^{-6}\,J$
  • C$6.25\times 10^{-6}\,J$
  • D$2.16\times 10^{-6}\,J$
JEE MAIN 2019, Medium
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