Three capacitors of capacitance $1\ \mu F$, $2 \ \mu F$ and $3\ \mu F$ are connected in series and a potential difference of $11 V$ is applied across the combination. Then, the potential difference across the plates of $1\ \mu F$ capacitor is......$V$
Medium
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(d) Equivalent capacitance $\frac{1}{{{C_{eq}}}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3}$
$==>$ ${C_{eq}} = \frac{6}{{11}}\,\mu F$
Charge supplied from battery $Q = \frac{6}{{11}} \times 11 = 6\,\mu C$
Hence potential difference across $1 \ \mu F$ capacitor $ = \frac{6}{1} = 6V$
$==>$ ${C_{eq}} = \frac{6}{{11}}\,\mu F$
Charge supplied from battery $Q = \frac{6}{{11}} \times 11 = 6\,\mu C$
Hence potential difference across $1 \ \mu F$ capacitor $ = \frac{6}{1} = 6V$
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