A car has a fresh battery of $e.m.f$. $12\, V$ and internal resistance of $0.05\, \Omega$. If the starter motor draws a current of $90\, A$, the terminal voltage when the starter is on will be ............... $V$
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$V = E - i.r = 12 - 90 \times 0.05 = 12 - 4.5 = 7.5\,V$.
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