MCQ
A carboxylic acid is converted into its anhydride using
- AThionyl chloride
- BSulphur chloride
- CSulphuric acid
- ✓Phosphorus pentoxide
$\begin{array}{*{20}{c}}
{RCOOH} \\
{RCOOH}
\end{array}\,\xrightarrow{{{P_2}{O_5}}}$ $\begin{array}{*{20}{c}}
{RCO} \\
{RCO}
\end{array} > O + {H_2}O$
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$\begin{array}{*{20}{c}}
{C{H_3}}\\
{|\,\,\,\,\,}\\
{{C_6}{H_5}C{H_2} - C - C{H_2} - C{H_3}}\\
{|\,\,\,\,\,}\\
{Br\,\,\,}
\end{array}$ $\xrightarrow[{{C_2}{H_5}OH}]{{{C_2}{H_5}ONa}}$
What is the $A$ product