What is the $A$ product
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[Given : Molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$, acetic acid $=60 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
${ }^{\mathrm{K}_{\mathrm{f}}} \mathrm{H}_2 \mathrm{O}: 1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$
$\mathrm{K}_{\mathrm{r}}$ acetic acid : $3.90 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$
freezing point: $\mathrm{H}_2 \mathrm{O}=273 \mathrm{~K}$, acetic acid $=290 \mathrm{~K}$ ]
Statement $(I)$ : Oxygen being the first member of group $16$ exhibits only $-2$ oxidation state.
Statement $(II)$ : Down the group $16$ stability of $+4$ oxidation state decreases and $+6$ oxidation state increases.
In the light of the above statements, choose the most appropriate answer from the options given below:
$(1)$ $\begin{matrix}
C{{H}_{3}} \\
|\,\,\,\,\,\, \\
ZNH\,C\,HC{{O}_{2}}H \\
\end{matrix}$ $(2)$ $\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{2}}N\,C\,HC{{O}_{2}}C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(3)$ $\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}{{C}_{6}}{{H}_{5}} \\
|\,\,\,\,\, \\
ZNH\,C\,HC{{O}_{2}}H \\
\end{matrix}$ $(4)$ $\begin{matrix}
C{{H}_{2}}{{C}_{6}}{{H}_{5}}\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{2}}N\,CHC{{O}_{2}}C{{H}_{2}}{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(i)$ Diastereomers $(ii)$ Geometrical isomers
$(iii)$ Epimers $(iv)$ Anomers
$(v)$ Enantiomers