Question
A carpenter had a board which measured $3m \times 2m$. She cut out a rectangular piece of $250cm \times 90cm$. What is the ratio of the area of cut out piece and the remaining piece?
✓
Answer
Given, board measure $= 3m \times 2m$
Area of board = Length $\times $ Breadth
$= 3 \times 2 = 6m^2$
She cut out a rectangular piece $= 250\ cm \times 90\ cm$
Area of the piece $= 250 \times 90\ cm^2$
$= 22500cm^2$ [$\because$ $1m^2$$= 10000\ cm^2$]
$=\frac{22500}{10000}\text{m}^2$
$=2.25\text{m}^2$
Remaining area of board $= (6 - 2.25)m^2$
$= 3.75m^2$
Ratio of the area of cut out piece to the remaining piece$=\frac{2.25\text{m}^2}{3.75\text{m}^2}$
$=\frac{225}{375}$
$=\frac{3}{5}$
$=3:5$
Area of board = Length $\times $ Breadth
$= 3 \times 2 = 6m^2$
She cut out a rectangular piece $= 250\ cm \times 90\ cm$
Area of the piece $= 250 \times 90\ cm^2$
$= 22500cm^2$ [$\because$ $1m^2$$= 10000\ cm^2$]
$=\frac{22500}{10000}\text{m}^2$
$=2.25\text{m}^2$
Remaining area of board $= (6 - 2.25)m^2$
$= 3.75m^2$
Ratio of the area of cut out piece to the remaining piece$=\frac{2.25\text{m}^2}{3.75\text{m}^2}$
$=\frac{225}{375}$
$=\frac{3}{5}$
$=3:5$
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