Question
A carton contains eight brown and four white eggs. Find the probability that an egg selected at random is:
(i) brown
(ii) white
(i) brown
(ii) white
✓
Answer
Number of brown eggs $=8$
Number of white eggs $=4$
Total Number of eggs $=8+4=12$
(i) $\mathrm{P}\left(\right.$ of getting a brown eggs) $=\frac{8}{12}=\frac{2}{3}$
(ii) $P$ (of getting a white eggs) $=\frac{4}{12}=\frac{1}{3}$
Number of white eggs $=4$
Total Number of eggs $=8+4=12$
(i) $\mathrm{P}\left(\right.$ of getting a brown eggs) $=\frac{8}{12}=\frac{2}{3}$
(ii) $P$ (of getting a white eggs) $=\frac{4}{12}=\frac{1}{3}$
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