[3 marks sum]

Question 13 Marks

A carton contains eight brown and four white eggs. Find the probability that an egg selected at random is:
(i) brown
(ii) white

Answer

Number of brown eggs $=8$
Number of white eggs $=4$
Total Number of eggs $=8+4=12$
(i) $\mathrm{P}\left(\right.$ of getting a brown eggs) $=\frac{8}{12}=\frac{2}{3}$
(ii) $P$ (of getting a white eggs) $=\frac{4}{12}=\frac{1}{3}$

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Question 23 Marks

A die is thrown, find the probability of getting:
a number greater than 4

Answer

A die has six numbers: $1,2,3,4,5,6$
$\therefore$ Number of possible outcomes $=6$
a number greater than 4
Numbers of favourable outcomes $=$ greater than four i.e. two number 5 and 6
$P(E)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$
$=\frac{2}{6}=\frac{1}{3}$

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Question 33 Marks

There are 8 marbles in a bag with numbers from 1 to 8 marked on each of them. What is the probability of drawing a marble with a number
(i) 3
(ii) 7

Answer

Total number of marbles $=8$
(i) Probability (of getting a marble with number 3 ) $=\frac{1}{8}$
(ii) Probability (of getting a marble with number 7 ) $=\frac{1}{8}$

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Question 43 Marks

A survey of 50 boys showed that 21 like tea while 29 dislike it. Out of these boys, one boy is chosen at random. What is the probability that the chosen boy
(i) likes tea
(ii) dislikes tea

Answer

Total number of boys $=50$
Number of boys like tea $=21$
Number of boys dislike tea $=29$
(i) Probability of boys like tea $=\frac{21}{50}$
(ii) Probability of boys dislike tea $=\frac{29}{50}$

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Question 53 Marks

A dice is thrown 20 times and the outcomes are noted as shown below:

Outcomes	1	2	3	4	5	6
No. of times	2	3	4	4	3	4

Now a dice is thrown at random, find the probability of getting:

Answer

$\because$ Total number of outcomes $=20$
(i) $P($ getting 3$)=\frac{4}{20}=\frac{1}{5}$
(ii) A number less than $3(1,2)$ will appear $=2+3=5$ times
$\therefore$ Probability $=\frac{5}{20}=\frac{1}{4}$
(iii) A number greater than $3(4,5,6)$ will appear $=4+3+4=11$ times
$\therefore$ Probability $=\frac{11}{20}$

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Question 63 Marks

A coin is tossed 80 times and the head is obtained 38 times. Now, if a coin tossed once, what will the probability of getting a head

Answer

$\because$ Total number of possible outcomes $=80$
and, the number of favourable outcomes of getting head $=38$
$\therefore$ Probability of getting a head $=\frac{\text { Number of favourable outcomes }}{\text { Total number of outcomes }}$
$=\frac{38}{80}=\frac{19}{40}$

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Question 73 Marks

A coin is tossed 80 times and the head is obtained 38 times. Now, if a coin tossed once, what will the probability of getting a tail

Answer

$\because$ Total number of possible outcomes $=80$
and, the number of favourable outcomes of getting a tail $=80-38=42$
$\therefore$ Probability of getting a tail $=\frac{\text { Number of favourable outcomes }}{\text { Total number of outcomes }}$
$=\frac{42}{80}=\frac{21}{40}$

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MATHS [3 marks sum]

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