A cell of negligible resistance and $e.m.f.$ $2$ $volts$ is connected to series combination of $2$, $3$ and $5\, ohm$. The potential difference in volts between the terminals of $3\, ohm$ resistance will be
A$0.6$
B$2/3$
C$3$
D$6$
Medium
Download our app for free and get started
A$0.6$
a Current supplied by cell $i = \frac{2}{{2 + 3 + 5}} = \frac{1}{5}\,A$
So potential difference across $3$ will be $V = \frac{{3 \times 1}}{5} = 0.6\,V$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$A$ battery is of $\mathrm{emf}$ $E$ is being charged from a charger such that positive terminal of the battery is connected to terminal $A$ of charger and negative terminal of the battery is connected to terminal $B$ of charger. The internal resistance of the battery is $r$.
A current of $6\, A$ enters one corner $P$ of an equilateral triangle $PQR$ having $3$ wires of resistance $2 \,\Omega$ each and leaves by the corner $R$. The currents $i_{1}$ in ampere is ........ .
Resistance in the two gaps of a meter bridge are $10\, ohm$ and $30\, ohm$ respectively. If the resistances are interchanged the balance point shifts by.............. $cm$
Temperature coefficient at $0\,^oC$ is $0.00125\,^oC^{-1}$. At a temperature of $25\,^oC$ its resistance is $1\,\Omega $. Find the temperature at which resistance is $1.2\,\Omega $
An ammeter $A$ of finite resistance, and a resistor $R$ are joined in series to an ideal cell $C$. $A$ potentiometer $P$ is joined in parallel to $R$. The ammeter reading is $I_0$ and the potentiometer reading is $V_0$. $P$ is now replaced by a voltmeter of finite resistance. The ammeter reading now is $I$ and the voltmeter reading is $V$.