A chain of length $L$ rests on a rough table. If $\mu $ be the coefficient of friction, the maximum friction of the chain that can hang over the table will be
Medium
Download our app for free and get started
Let $m$ be the mass per unit length of the chain.
Suppose the length of the hanging chain is $l.$ Then,
$\mu(\mathrm{L}-\ell) \mathrm{mg}=\ell \mathrm{mg}, \mu \mathrm{L}=(\mu+1) \ell$
$\therefore \frac{\ell}{L}=\frac{\mu}{\mu+1}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A road is banked at an angle of $30^o$ to the horizontal for negotiating a curve of radius $10\sqrt 3 m$. At what velocity will a car experience no friction while negotiating the curve? ............... $km/hr$View Solution
- 2View SolutionA car is moving with uniform velocity on a rough horizontal road. Therefore, according to Newton's first law of motion
- 3A child weighing $25$ kg slides down a rope hanging from the branch of a tall tree. If the force of friction acting against him is $2\, N$, ........ $m/s^2$ is the acceleration of the child (Take $g = 9.8\,m/{s^2})$View Solution
- 4A body of mass $5\, kg$ is moving in a circle of radius $1\,m$ with an angular velocity of $2$ radian/sec. The centripetal force is ......... $N$View Solution
- 5A body starts from rest on a long inclined plane of slope $45^o$ . The coefficient of friction between the body and the plane varies as $\mu = 0.3\,x$ . where $x$ is distance travelled down the plane. The body will have maximum speed ( for $g = 10\,m/s^2$ ) when $x=$ ........ $m$View Solution
- 6A body of mass $2 \,kg$ is kept by pressing to a vertical wall by a force of $100\, N$. The coefficient of friction between wall and body is $0.3.$ Then the frictional force is equal to ........ $N$View Solution
- 7A block of mass $m$ lying on a rough horizontal plane is acted upon by a horizontal force $P$ and another force $Q$ inclined an at an angle $\theta $ to the vertical. The minimum value of coefficient of friction between the block and the surface for which the block will remain in equilibrium isView Solution
- 8For the given figure, if block remains in equilibrium position then find frictional force between block and wall ........ $N$View Solution
- 9When $F = 2N$, the frictional force between $10 kg$ block and $5 kg$ block is ...... $N$View Solution
- 10A block of mass $M$ placed on rough surface of coefficient of friction equal to $3$ . If $F$ is the $(4/5)$ of the minimum force required to just move. Find out the force exerted by ground on the blockView Solution
