A charge $3$ coulomb experiences a force $3000$ $N$ when placed in a uniform electric field. The potential difference between two points separated by a distance of $1$ $cm$ along the field lines is.....$V$
Medium
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Electric force $F=q E$
given, $F=3000 N, q=3 C$
$\therefore E=\frac{F}{q}=\frac{3000}{3}=1000 \mathrm{V} / \mathrm{m}$
Potential difference, $V=E d$ where $d=0.01 m$
$\therefore V=1000 \times 0.01=10 V$
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