A charge of $40\,\mu \,C$ is given to a capacitor having capacitance $C = 10\,\mu \,F$. The stored energy in ergs is
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(b) $U = \frac{{{Q^2}}}{{2C}} = \frac{{{{(40 \times {{10}^{ - 6}})}^2}}}{{2 \times {{10}^{ - 6}} \times 10}} = \frac{{16 \times {{10}^{ - 10}}}}{{2 \times {{10}^{ - 5}}}} = 8 \times {10^{ - 5}}\,J$
$ = 8 \times {10^{ - 5}} \times {10^7} = 800\,erg$
$ = 8 \times {10^{ - 5}} \times {10^7} = 800\,erg$
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