A charge of $5\,C$ experiences a force of $5000\,N$ when it is kept in a uniform electric field. .........$V$ is the potential difference between two points separated by a distance of $1\,cm$
A$10$
B$250$
C$1000$
D$2500$
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A$10$
a (a) $F = QE = \frac{{QV}}{d}$ $==>$ $5000 = \frac{{5 \times V}}{{{{10}^{ - 2}}}}$ $==>$ $V = 10\,volt$
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