d
$\alpha=\frac{q}{m},$ path of the particle will be a helix of time period,
$T=\frac{2 \pi m}{B_{0} q}=\frac{2 \pi}{B_{0} \alpha}$
The given time $t=\frac{\pi}{B_{0} \alpha}=\frac{T}{2}$
Coordinates of particle at time $t=T / 2$ would be $\left(v_{x} T / 2,0,-2 r\right)$
Here, $r=\frac{m v_{0}}{B_{0} q}=\frac{v_{0}}{B_{0} \alpha}$
$\therefore$ The coordinate are $\left(\frac{v_{0} \pi}{B_{0} \alpha}, 0, \frac{-2 v_{0}}{B_{0} \alpha}\right)$
