A closed pipe and an open pipe have their first overtones identical in frequency. Their lengths are in the ratio
Medium
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(c) If is given that First over tone of closed pipe = First over tone of open pipe
$\Rightarrow$$3\left( {\frac{v}{{4{l_1}}}} \right) = 2\left( {\frac{v}{{2{l_2}}}} \right)$;
where $l_1$ and $l_2$ are the lengths of closed and open organ pipes
hence $\frac{{{l_1}}}{{{l_2}}} = \frac{3}{4}$
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