MCQ
A closed pipe and an open pipe have their first overtones identical in frequency. Their lengths are in the ratio
- A$1:2$
- B$2:3$
- ✓$3:4$
- D$4:5$
$\Rightarrow$$3\left( {\frac{v}{{4{l_1}}}} \right) = 2\left( {\frac{v}{{2{l_2}}}} \right)$;
where $l_1$ and $l_2$ are the lengths of closed and open organ pipes
hence $\frac{{{l_1}}}{{{l_2}}} = \frac{3}{4}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


$\text{A} = 2.5\text{ms}^{-1} \pm 0.5\text{ms}^{-1}$
$\text{B} = 0.10\text{s} \pm 0.01\text{s}$
The value of A B will be,$(0.25 \pm 0.08)\text{m}.$
$(0.25 \pm 0.5)\text{m}.$
$(0.25 \pm 0.05)\text{m}.$
$(0.25 \pm 0.135)\text{m}$