A coil having $100$ turns, area of $5 \times 10^{-3} \mathrm{~m}^2$, carrying current of $1 \mathrm{~mA}$ is placed in uniform magnetic field of $0.20 \mathrm{~T}$ such a way that plane of coil is perpendicular to the magnetic field. The work done in turning the coil through $90^{\circ}$ is . . . . . . $\mu \mathrm{J}$.
  • A$100$
  • B$99$
  • C$200$
  • D$199$
JEE MAIN 2024, Diffcult
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