$B=\frac{\mu}{4 \pi} \mathrm{q} \frac{\mathrm{v} \times \mathrm{r}}{\mathrm{r}^{2}}$
$\mathrm{So}, \quad \mathrm{B} \perp \mathrm{v}$

Reason : Any two charged particles having equal kinetic energies and entering a region of uniform magnetic field $\overrightarrow B $ in a direction perpendicular to $\overrightarrow B $, will describe circular trajectories of equal radii.
Reason $(R):$ Opposite currents carrying wires repel each other.