A coin placed on a rotating table just slips when it is placed at a distance of $1\,cm$ from the center. If the angular velocity of the table in halved, it will just slip when placed at a distance of from the centre $............\,cm$
JEE MAIN 2023, Medium
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$f _{ s \max }=\mu mg = m \omega^2 R \Rightarrow R =\frac{\mu g }{\omega^2}$
So if $\omega$ becomes $\frac{\omega}{2}, R$ will become $4 R$.
So distance from the center will be $4\,cm$.
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