MCQ
A complex containing $K^+, Pt(IV)$ and $Cl^-$ is $100\%$ ionised giving $i = 3$. Thus, possible complex is
- A$K_2[Pt\, Cl_4]$
- ✓$K_2[Pt\, Cl_6]$
- C$K_3[Pt\, Cl_5]$
- D$K[Pt\, Cl_3]$
(2) $K _{2} P t Cl _{6} \rightarrow 2 K ^{+}+\left[ P _{ t } Cl _{6}\right]^{2-} ; i =1+2=3$
In $(1)$, oxidation number of $Pt =2$
In $(2),$ the oxidation number of $P t=4$
Therefore, $K _{2}\left[ P t Cl _{6}\right]$ is the correct answer.
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Reason : There is delocalisation of electrons from filled $d$ orbitals into the empty orbitals on the $CO$ ligands.
${H_3}C - C \equiv CH\,\xrightarrow[{HgS{O_4}}]{{{H_2}O,\,{H_2}S{O_4}}}\,\mathop {Intermediate}\limits_{(A)} \,$$ \to \,\mathop {\Pr oduct}\limits_{(B)} $
| Process | $\Delta H / kJ\,mol ^{-1}$ | $\Delta S / J K^{-1}$ |
| $A$ | $-25$ | $-80$ |
| $B$ | $-22$ | $40$ |
| $C$ | $25$ | $-50$ |
| $D$ | $22$ | $20$ |
The number of non-spontaneous process from the following is $.....$