MCQ
A compound contains $C = 90\% $ and $H = 10\% $. Empirical formula of the compound is
- A${C_3}{H_{10}}$
- B$C{H_2}$
- C${C_3}{H_2}$
- ✓${C_3}{H_4}$
| Elements | No. of Moles | Simple ratio |
|
$C = 90\%$ |
$90/12 = 7.5$ |
$ 7.5/7.5 = 1 × 3 = 3$ |
|
$H = 10\%$ |
$10/1 = 10$ |
$10/7.5 = 1.33 × 3 = 4$ |
Empirical formula = ${C_3}{H_4}$
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