MCQ
A compound has $3$ chiral carbon atoms. The number of possible optical isomers it can have
- A$3$
- B$2$
- ✓$8$
- D$4$
✓
Answer
Correct option: C.
$8$
c
(c) The number of possible optical isomers $ = {2^n}$
(where ‘$n$’ is the number of chiral $c-$ atoms) $ = {2^3} = 8$
(c) The number of possible optical isomers $ = {2^n}$
(where ‘$n$’ is the number of chiral $c-$ atoms) $ = {2^3} = 8$
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