MCQ
A compound ‘$X$’ on ozonolysis forms two molecules of $HCHO$. Compound ‘$X$’ is
- ✓${C_2}{H_4}$
- B${C_2}{H_2}$
- C${C_2}{H_6}$
- D${C_6}{H_6}$
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Given: $\Delta H ^0=-54.07\,kJ\,mol ^{-1}$
$\Delta S ^{\circ}=10\,JK ^{-1}\,mol ^{-1}$
(Take $2.303 \times 8.314 \times 298=5705$ )