MCQ
A concave mirror produces an image of an object such that the distance between the object and image is 20 cm . If the magnification of the image is ' -3 ', then the magnitude of the radius of curvature of the mirror is :
  • A
    3.75 cm
  • B
    30 cm
  • C
    7.5 cm
  • D
    15 cm

Answer

D.
Image
$\mathrm{m}=-3=-\frac{\mathrm{v}}{\mathrm{u}}$ and $\mathrm{v}-\mathrm{u}=20 \mathrm{~cm}$
$\mathrm{f}=\frac{\mathrm{vu}}{\mathrm{v}+\mathrm{u}}=\frac{(-30)(-10)}{-30-10}$
$\therefore \mathrm{R}=+15$

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