$\frac{1.314}{\frac{197}{3}}=\frac{\mathrm{Q}}{1 \mathrm{~F}}$
$\mathrm{Q}=2 \times 10^{-2} \mathrm{~F}$
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$(P)\, Fe(CO)_5\,\,\, (Q)\,CO\,\,\, (R)\, H_3B \leftarrow CO\,\,\,(S)\, [Mn(CO)_5]^-$
The curves $M$ and $N$ represent the variation of energy with reaction coordinate for the reaction in absence and presence of catalyst
Which value represents the activation energy $(E_a)$ for the backward reaction in the presence of catalyst
$C{l_2} + 2B{r^ - }\left( {aq} \right) \to 2C{l^ - }\left( {aq} \right) + B{r_2}$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with