A converging lens of focal length 5cm is placed at a distance of 20cm from a screen. How far from the lens should an object be placed so as to form its real image on the screen?
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f = 5cm u = -20cm v = +v (Since image is real) Lens formula, $\frac{1}{\text{v}}-\frac{1}{\text{u}}=\frac{1}{\text{f}}$$\frac{1}{\text{v}}-\frac{1}{-20}=\frac{1}{5}$
$\frac{1}{\text{v}}=\frac{1}{5}-\frac{1}{20}$
$\frac{1}{\text{v}}=\frac{4-1}{20}=\frac{3}{20}$
$\text{v}=6.66$
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