MCQ
A copper solid cube of $60\,\, mm$ side is subjected to a pressure of $2.5 \times 10^7\, Pa$. If the bulk modulus of copper is $1.25 \times 10^{11}\, N/m^2$, the change in the volume of cube is
  • A
    $-43.2\, m^3$
  • $-43.2\, mm^3$
  • C
    $-43.2\, cm^3$
  • D
    $-432\, mm^3$

Answer

Correct option: B.
$-43.2\, mm^3$
b
$\mathrm{B}=-\frac{\Delta \mathrm{PV}}{\Delta \mathrm{V}} \Rightarrow \Delta \mathrm{V}=-\frac{\Delta \mathrm{PV}}{\mathrm{B}}$

$=-\frac{2.5 \times 10^{7}}{1.25 \times 10^{11}} \times(60)^{3} \mathrm{mm}^{3}=-43.2 \mathrm{mm}^{3}$

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